"intelligent" disk drives

[Tony Duell]

> IIRC, the 2.8M is vertical recording, with a Barium Ferrite diskette.
> (also called "4M" (unformatted capacity) by NeXT)
> If'n anybody wants to call it "2.88M", then multiply 2 * 80 * 36 * 512
> and tell me exactly how many bytes are in your "megabyte"s.

Since that's esactly twice the capacity of a MS-DOS format HD 3.5" disk 
(36 sectors/track as against 18), I assume the answer to your quesiton is 
1024000

-tony