"intelligent" disk drives

[Fred Cisin]

> > IIRC, the 2.8M is vertical recording, with a Barium Ferrite diskette.
> > (also called "4M" (unformatted capacity) by NeXT)
> > If'n anybody wants to call it "2.88M", then multiply 2 * 80 * 36 * 512
> > and tell me exactly how many bytes are in your "megabyte"s.
On Mon, 19 Nov 2007, Tony Duell wrote:
> Since that's esactly twice the capacity of a MS-DOS format HD 3.5" disk
> (36 sectors/track as against 18), I assume the answer to your quesiton is
> 1024000

I don't think that there is any question that 102400 is a totally
indefensible, irresponsible, and ridiculous number for defining a
"Megabyte".