using new technology on old machines

Noel Chiappa jnc at
Wed Jun 17 09:08:15 CDT 2015

    > From: Dave G4UGM

    > I found it easier to think of it in DC terms. So the Cap charges
    > through R5 + R3 and R9 + R8.
    > As the Cap charges the voltage on the base of Q1 rises until it turns
    > on, which then turns on Q2.
    > At this point the cap is then charged (or discharged) in the reverse
    > direction via Q2, D5 and R4 until Q1 turns off.....

I'm clearly never going to be any good at analog stuff! ;-) Even with what
looks (on the surface) to be a wonderfully clear explanation of how the
circuit works, I still can't really grok how it operates!

I mean, I can tell from the polarity on the cap that the collector of Q2 must
be at a higher voltage than the base of Q1, but I am utterly failing to
understand how the cap discharges through Q2. And as the cap charges (i.e.
the voltage across it increases), how does the voltage on the base of Q1
increase - surely it must be decreasing (since it's tied to the negative side
of the cap, which is experiencing a voltage increase across itself)?

Like I said, I apparently don't have the gene for analog... :-)


More information about the cctalk mailing list