11/34 failing trap test

[Julian Wolfe]

On Sep 22, 2006, at 12:16 PM, Don North wrote:

> Julian Wolfe wrote:
>> Okay, it halts with 20 in the octal display.  Is that the address?
>>
>> I guess I need to take this one step at a time.
>>
>> On Sep 20, 2006, at 1:39 AM, Don North wrote:
>>
>
> Ok, this means that the halt instruction was at 16(8) and probably
> came from the trapcatcher setup at 14(8). You can verify this by
> examining location 14(8) and see that is has a 16(8) in it.

I did that and got exactly as expected.
>
> 14(8) is the vector for the BPT instruction. Now you need to examine
> the SP and look on the stack at (SP) to find the saved PC of where
> the actual trap occurred. This should be back somewhere in the program
> code (if you are lucky). It could be you are unlucky :-(, your CPU  
> went
> wild and just happened to run across an instruction word with an
> opcode of 000003 (which is BPT).

Examining the SP gives me a value of 470(8) on the display. Now, from  
what I understand, I should be looking for this address in the  
listing, correct?

Here is where I have difficulty; it seems to jump from 342(8) to 500 
(8) in the instruction listing.  Did my CPU go nuts, or am I just  
interpreting this wrong?

I am referring to the gap between lines 107 and 112 on page 5 of the  
bitsavers copy of the instruction listing.

Thanks again for your help.