I am now Annoyed [Re: Old oscilloscope help: ideas sought]

der Mouse mouse at Rodents.Montreal.QC.CA
Sun Mar 4 22:23:13 CST 2007


>> Well, yes - since it would be drawing (to a first approximation)
>> zero current.
> Not so.  There will be an out-of-phase current due to the inductance
> of the primary winding.

Yes; that's why I said "to a first approximation" - a transformer with
totally open secondaries is not quite a resistive load, but the current
drawn is generally comparatively small.

> IIRC, though, you've got a leak (or short) to earth from some point
> in the HV widning, and another point on that winding (the centre-tap
> of the B+ part) is deliberately earthed.

Yes - when it was in-circuit.  Not when it's sitting disconnected,
which was the circumstance under which I observed the excessive draw.

> That can't be right.

Agreed.

> And I'll bet that short-to-reath is not just on one turn, in other
> words you also have shorted turns there.

I agree, especially in view of the "open-circuit" draw. :)

> The Z-modulation input is an external brightness control input, used
> for some special applications.

I once built one. :)  (It was a 1Kx1 RAM with circuitry to scroll
through all 1K bits, effectively turning it into a 1Kbit shift
register, with the data bit controlling the Z input on the 'scope and
the X sweep generator triggered by the carry-out from the address
counter.  Get the clock frequencies about right and hook the input up
to a ham's CW sending key and you get a nice little graphic Morse
display scrolling past.)

>> (The unconnected final winding of the transformer is actually the
>> filament winding for the rectifier whose cathode is shown connected to
>                                           ^^^^^^^
> Don't you mean anode (plate to you) here?

No.  Cathode, as in, the part that emits electrons.  Which in a
filament valve rectifier will of necessity be the filament, so the
filament winding connected to that point will peforce be that for the
rectifier whose cathode is that filament.

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